Toothpickboy4452 Toothpickboy4452

03-07-2018
Mathematics

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Suppose that a is a nonzero constant for which the equation ax^2+20x+7=0 has only one solution. find this solution.

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konrad509 konrad509

03-07-2018

[tex]\Delta=0\\\\ \Delta=20^2-4\cdot a\cdot7=400-28a\\ 400-28a=0\\ 28a=400\\ a=\dfrac{400}{28}=\dfrac{100}{7} [/tex]

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