Respuesta :

It is given that [tex] P(A\cap B)=\frac{4}{7} \\
P(B)=\frac{7}{8} [/tex]

Now, the conditional probability,

[tex] P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{4/7}{7/8} =\frac{32}{49} [/tex].

The correct choice is (C).

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