corinam9851 corinam9851
  • 02-04-2019
  • Chemistry
contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

jamuuj jamuuj
  • 11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05  

m2=0.015 and

v2=25.00mL  

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

    = 7.50 mL

Answer Link

Otras preguntas

Write the equation of the circle with center(-3,-2) and (4,5) a point on the circle
can someone list out a bunch of facts about mountains for me?
18) Do all bacterial cells have this circular DNA? Explain.
Need help with this math problem
Write an argument for arguing with people for learning online courses? Thesis is, Online learning has become one of the most popular ways of gaining access to a
What is scouts full name?​
Write a possible polynomial function in factored form with roots 0, -5, and 9.
Why did the United States become involved in South and Central American affairs? They felt that Latin American ports were of greater strategic value than Pac
Please help ^^ thank you
simplif (x2+16)(x2_16) =?