Answer:
[tex]\large\boxed{\dfrac{18}{2x-6}=\dfrac{9}{x-3}}[/tex]
Step-by-step explanation:
[tex]\dfrac{18}{2x-6}=\dfrac{18\!\!\!\!\diagup^9}{2\!\!\!\!\diagup_1(x-3)}=\dfrac{9}{x-3}[/tex]
