Respuesta :

[tex]\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=\frac{2}{3} \end{cases}\implies A=\left( \cfrac{2}{3} \right)^2\implies A=\cfrac{2^2}{3^2}\implies A=\cfrac{4}{9}[/tex]

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