Answer:
Step-by-step explanation:
[tex]\vec{BC}(6 - 6, 2 -(-5)) = \vec{BC}(0, 7)\\\vec{AB}(6 -(-1), -5 -(-5)) = \vec{AB}(7, 0)\\\mid \vec{BC} \mid - \mid \vec{AB} \mid = \sqrt{(0^2 + 7^2)} - \sqrt{7^2 + 0^2} = \sqrt{49} - \sqrt{49} = 0[/tex]
So the distance is 0 units.
