Respuesta :

Willchemistry
Molar mass ammonia:

NH₃ = 17.031 g/mol

[tex]n = \frac{m}{M} [/tex]

[tex]n = \frac{1.2*10^3 g}{17.031 g/mol} [/tex]

[tex]n = 70.459 [/tex] moles

hope this helps!