[tex]x + 3y - 12 = 0[/tex]
Step-by-step explanation:
[tex] \frac{1}{3}x + y = 4 \\ \\ \frac{1}{3} x + y - 4 = 0 \\ \\ x + 3y - 12 = 0 \\ \\ x + 3y - 12 = 0[/tex]
