A) Differentiating the given equation ds/dt=-32t Which is the expression for velocity, hence the velocity of the object will be -32t at time t, B) When the object hits the ground, the distance above the ground I.e s equals 0, returning the value in given equation 0=167-16tsquare T=3.23 seconds C) Returning the value from b) in to equation form a) Ds/dt=-32t V=-32*3.2 V=-102.4m/sec squares In case you are wondering why the answer is negative, usually when velocity is positive, distance increases, but in this equation the distance I.e above the ground decreases with increase in velocity.
