Answer:
[tex]2x^3+8x^2-3x=0[/tex]
Step-by-step explanation:
[tex]2x (2x^2+8x-6)=2\\multiply-all-in-bracets-by-2x\\4x^3+16x^2-6x=2\\devide-all-by-2\\2x^3+8x^2-3x=0[/tex]
