Respuesta :

leena

Answer:

    0.000170 mol

Explanation:

This problem can be solved using dimensional analysis:

3.25g CuS × [tex]\frac{1 mol CuS}{95.61 g CuS}[/tex] ×[tex]\frac{1 mol SiS_{2} }{2 mol CuS}[/tex] = 0.000170 mol [tex]SiS_{2}[/tex]

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