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04-06-2020
Mathematics

contestada

Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi

A. No solution
B. Infinitely many solutions
C. 0, 2pi/3, 4pi/3, 2pi
D. 2pi/3, 4pi/3

Solve sin2 2θ1cos2θ on the interval 0ltθlt2pi A No solution B Infinitely many solutions C 0 2pi3 4pi3 2pi D 2pi3 4pi3 class=

Respuesta :

Paigedros Paigedros

05-06-2020

I can’t see the picture sorry

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