Dimajago Dimajago

03-07-2020
Mathematics

contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

EpicMinion900 EpicMinion900

03-07-2020

Answer:

21

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

Answer Link

Otras preguntas

Please simplify. [tex]\frac{y10}{y7}[/tex] A. [tex]y^{3}[/tex] B. [tex]y^{17}[/tex] C. [tex]y^{-3}[/tex] D. [tex]y^{70}[/tex]

The sum of three consecutive integers is 105. What are the three integers?

Latoya made $221 for 17 hours of work. At the same rate, how much would she make for 5 hours of work?

Find the output, h, when the input, x, is -18. h = 17+x\6

Evaluate x-2 for x=8

Hey guys, I'm struggling on this one, i know you have to factorise, but in what order? Thank you :)

Which is the graph of 2x + 3y > -3?

Write the quadratic equation whose roots are 4 and 5, and whose leading coefficient is 4.

Mike Karanikolas wants to enter the French market with his usual strategy of using influencers. Two influencers are considered to be hired. The first one is a y

Which nursing intervention is most important to include in the plan of care for a child with acute glomerulonephritis A. encourage fluid intake b. promote comp