Answer:
C'(2, 1 )
Step-by-step explanation:
Assuming the dilatation is centred at the origin then multiply the coordinates of C by [tex]\frac{1}{3}[/tex] , that is
C(6, 3 ) → C'( [tex]\frac{1}{3}[/tex] (6), [tex]\frac{1}{3}[/tex] (3) ) → C'(2, 1 )
