cblack4real
cblack4real cblack4real
  • 01-11-2020
  • Mathematics
contestada

If the equation y² - (K-
2y + 2k +1 = 0
with equal roots find the value of k​

Respuesta :

Lightning25346
Lightning25346 Lightning25346
  • 01-11-2020

Answer:

y² - (K-  2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

Answer Link

Otras preguntas

अभिलेख र जटिल को अर्थ के हो ​
Your ability to drive safely has nothing to do with your emotional state?
At the concert, there are 75 more girls than boys. If the ratio of girls to boys is 4:1, how many girls are at the concert? And how many boys are at the conce
how many states were in the union when edison gave this quiz in the 1920s?
what is the eastern most of the great lakes?
How did the British attempt to convince African and Native Americans to join their army against the patriots?
How do you compare a lemon with an almond? Please tell me I want to know.
A father and mother are both heterozygous brown eyes. If they have 24 kids. What percent of the offspring will have blue eyes.
Are 0.2 and 1 /5 equivalent? Explain your answer in complete sentences.
What is the slope of the line and what does it mean in this situation (2,4) through (5, 10)