Answer:
x = 2
Step-by-step explanation:
[tex] log_{3}x(x+ 30) = log_{3}64 \\ x(x + 30) = 64 \\ {x}^{2} + 30x - 64 = 0 \\ x = 2 \: or \: x = - 32[/tex]
-32 is rejected because in logarithms you cannot use negative value so x=2
