Respuesta :

caylus

Hello,

[tex]a\neq 0\\\\\dfrac{\dfrac{1}{a+1} }{a-\dfrac{1}{a+\dfrac{1}{a} }} \\\\\\=\dfrac{\dfrac{1}{a+1}}{\dfrac{a(a^2+1)+a} {a^2+1} }\\\\\\=\dfrac{a^2+1}{a(a+1)(a+2)}[/tex]