Answer:
r= [tex]\sqrt{(\sqrt{3})^{6} +(1)^{2} } =\sqrt{4} =2[/tex]
(2)^5(cos(330.6)+isin(330.6))
=64(Cos1350+iSin1350)
64(cos180+isin180)
=64(-1+0)= -64
Step-by-step explanation:
