autumnrdill autumnrdill

02-11-2021
Mathematics

contestada

Maximize
P=x1+2x2
subject to

4x1−3x2≤15
5x1+2x2≤25
−2x1+5x2≤33
5x1+x2≤7
x1, x2≥0

Respuesta :

Аноним Аноним

02-11-2021

Answer:

Step-by-step explanation:

4x1−3x2≤15 5x1+2x2≤25 = 40\

−2x1+5x2≤33 + 40= 94

5x1+x2≤7 x1,+94 = 108

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