Answer:
[tex]t^{9}s^{8}[/tex]
Step-by-step explanation:
[tex]s^{0} = 1; u^{-1} = \frac{1}{u} \\1(t)(\frac{1}{u})(s^{8})(t^{8})(u)\\\frac{(t^{1+8})(s^{8})(u)}{u}\\t^{9}s^{8}[/tex]
