Respuesta :

LammettHash

If each of A, B, and C are mutually independent, then

P(A and B and C) = P(A) P(B) P(C)

so that the probability of the three-way intersection is

P(A and B and C) = 0.66 × 0.52 × 0.78 = 0.267696 ≈ 0.27