Respuesta :

LammettHash
[tex]h(x)=(f\circ g)(x)[/tex]
[tex]\sqrt{x+5}=\sqrt{g(x)+2}[/tex]
[tex]x+5=g(x)+2[/tex]
[tex]g(x)=x+3[/tex]

Just to check this is correct:

[tex](f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)[/tex]

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