VaileK163597
VaileK163597
03-11-2022
Mathematics
contestada
(300/m) + 44n m=15 n=4
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JadienN175683
JadienN175683
03-11-2022
Solve (300/m) + 44n where m = 15 and n = 4
[tex]\begin{gathered} (\frac{300}{m})+44n \\ \text{Substitute for the values of m and n, and you have;} \\ (\frac{300}{15})+44(4) \\ 20+176 \\ 196 \end{gathered}[/tex]
The solution to the expression is 196
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