[tex]f(x)=\frac{1}{x+2}[/tex]
To find f(3 + h) we need to substitute x = 3 + h, into the function, as follows:
[tex]\begin{gathered} f(x)=\frac{1}{(3+h)+2} \\ \text{ Combining similar terms:} \\ f(x)=\frac{1}{h+(3+2)} \\ f(x)=\frac{1}{h+5} \end{gathered}[/tex]
