caroldosker
caroldosker
03-04-2017
Mathematics
contestada
I need to simplify sec^2(x)/sec^2(x)-1
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LammettHash
LammettHash
03-04-2017
[tex]\dfrac{\sec^2x}{\sec^2x-1}=\dfrac{\sec^2x}{\tan^2x}=\dfrac{\frac1{\cos^2x}}{\frac{\sin^2x}{\cos^2x}}=\dfrac1{\sin^2x}=\csc^2x[/tex]
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