Isabella10
Isabella10
03-11-2015
Mathematics
contestada
5 consecutive intergers whose sum is 195
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TSO
TSO
03-11-2015
x + (x+1) + (x+2) + (x+3) + (x+4) = 195
5x + 10 = 195
5(x+2) = 195
x + 2 = 39
x = 37
The 5 consecutive integers whose sum is 195 are
37, 38, 39, 40, 41
.
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