Hussain11
Hussain11
02-02-2018
Mathematics
contestada
I need help with problem plz
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sqdancefan
sqdancefan
06-02-2018
The area of revolution is the integral of 2π(radius)(differential of arc length). [tex] \int\limits^2_1 {2 \pi t^3 \sqrt{(9/4)t^4 +36)}} \, dt[/tex] = (2π/27)*(72^(3/2) -38.25^(3/2)) ≈ 87.1215
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