TRUEBOSS72
TRUEBOSS72
01-05-2018
Mathematics
contestada
Please help me with this
Respuesta :
mkryukova19
mkryukova19
01-05-2018
y=3(x²+10x)+71
Now we need to complete square for (x²+10)
It should look like this
a²+2ab+b²=(a+b)²
y=3(x²+2*5x+5²)-3*5²+71
y=3(x+5)²-75+71
y=3(x+5)²-4
Vertex has coordinates x=-5, y=-4.
Vertex in this case is the extreme value
(-5,-4)
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